Cwna 109 Practice Test Part 1 Questions 1 40

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CWNA-109 PRACTICE TEST PART 1 QUESTIONS 1-40 Question 1: A wireless engineer compares two signals traveling in free space. Signal A is at 2.4 GHz and Signal B is at 5 GHz. Which statement about the...

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CWNA-109 PRACTICE TEST

PART 1 QUESTIONS 1-40

Question 1: A wireless engineer compares two signals traveling in free space. Signal A is at 2.4 GHz and Signal B is at 5 GHz. Which statement about their wavelengths is correct?

Choices:

1) Wavelength cannot be compared without knowing transmit power.2) Signal B has the longer wavelength.3) Both signals have the same wavelength because they travel at the same speed.4) Signal A has the longer wavelength.

Correct Answer: Signal A has the longer wavelength.

Explanation: Wavelength is inversely proportional to frequency. Because 2.4 GHz is lower in frequency than 5 GHz, the 2.4 GHz signal has a longer wavelength.Page 1

Question 2: During a site survey, a strong WLAN signal reaches a receiver after

bouncing from a large metal wall. Which RF behavior best describes this path?

Choices:

1) Re�ection 2) Absorption 3) Refraction 4) Di�raction

Correct Answer: Re�ection

Explanation: Re�ection occurs when an RF wave strikes a large smooth object, such as a metal wall, and changes direction by bouncing from the surface.Question 3: A client receives several delayed copies of the same transmitted signal because RF energy followed di�erent paths through a building. What phenomenon is occurring?

Choices:

1) Free-space path loss 2) Multipath 3) Frequency hopping 4) Polarization diversity

Correct Answer: Multipath

Explanation: Multipath occurs when re�ected, di�racted, or scattered copies of a signal arrive at the receiver at di�erent times and phases. It can cause constructive or destructive e�ects.Page 2

Question 4: Approximately how much RF power is represented by 20 dBm?

Choices:

1) 20 mW

2) 1 W

3) 100 mW 4) 200 mW

Correct Answer: 100 mW

Explanation: 0 dBm equals 1 mW. Adding 10 dB multiplies power by 10, so 10 dBm is 10 mW and 20 dBm is 100 mW.Question 5: An access point transmits at 17 dBm. The RF cable introduces 2 dB of loss and the antenna provides 5 dBi of gain. Ignoring other losses, what is the approximate EIRP?

Choices:

1) 20 dBm 2) 24 dBm 3) 10 dBm 4) 14 dBm

Correct Answer: 20 dBm

Explanation: EIRP is transmitter output minus cable loss plus antenna gain: 17 dBm - 2 dB + 5 dBi = 20 dBm.Page 3

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