Question 1
If the input voltages of an op-amp are identical and the output voltage is 0Vdc. The op-amp is
Correct Answer:
Balanced
Explanation:
When the input voltages of an op-amp are identical, the differential input voltage is zero. In an ideal op-amp, the output is proportional to this difference, so zero difference means the output sits at zero volts, provided the device is not driven into saturation by offset errors. This situation is described as the op-amp being balanced: the two inputs are at the same potential, so there is no differential drive pushing the output away from a harmless, linear operating point. The given scenario—inputs equal and output at 0 V—fits perfectly with a balanced, linear condition. If the output were at a supply rail, that would indicate saturation, and if the inputs differed, the device wouldn’t be balanced.
Question 2
If the circuit load resistor is varied within design limits, the circuit voltage gain remains the same.
Correct Answer:
remains the same
Explanation:
In a negative-feedback op-amp circuit, the voltage gain is set by the feedback network—the ratio of the resistors in the feedback path—rather than by what the load does at the output. The op-amp adjusts its output so that the voltage at the inverting input matches the input voltage, enforcing a fixed relationship between input and output determined by that resistor ratio. The load simply draws current from the output; as long as the load is within the amplifier’s ability to drive (no excessive current, no saturation or output impedance effects beyond design limits), the feedback keeps the same output voltage ratio, so the gain stays constant. If the load were to demand more current than the device can supply, you’d see a change due to output limitations, but within design limits the gain remains the same.
Question 3
Voltage comparators perform as
Correct Answer:
Level Detectors
Explanation:
Voltage comparators are designed to decide which of two voltages is higher and to produce an output that reflects that decision. This makes them act as level detectors: they monitor a signal against a fixed reference and flip their output when the signal crosses that threshold. When the input surpasses the reference, the output switches to a high level; when it falls short, the output goes low. This threshold-crossing behavior is what you use to sense that a particular voltage level has been reached or exceeded. They’re not meant to amplify signals like amplifiers, not meant to generate repeating waveforms like oscillators, and not meant to accumulate input over time like integrators.
Question 4
To adjust the output offset voltage of an op-amp, connect circuit inputs to
Correct Answer:
Circuit common
Explanation:
To null or adjust the output offset, you want the two input terminals to sit at the same potential so any remaining output is due only to the offset voltage inside the amplifier. Tying both inputs to the circuit common provides that common reference point, making the input differential effectively zero. With both inputs at the same level, you can use offset-trim provisions (if present) to dial the output back to zero. If you connect an input to the power supply, the inputs aren’t forced to be equal and the amplifier may drive to a rail or behave unpredictably. Connecting to the output node would disturb the feedback behavior and won’t set the inputs equal. Grounding both inputs works if ground is the same as the circuit’s common reference, but the intended and reliable practice is to use the circuit common, which is the designated reference for offset adjustment.
Question 5
For a Multiple-Feedback (MFB) active filter, what do component values primarily determine?
Correct Answer:
Quality factor (Q) and center frequency.
Explanation:
In a multiple-feedback active filter, the passive network around the op-amp sets the locations of the poles of the transfer function. Those pole locations determine the center frequency and how sharply the filter responds, i.e., the Q factor. So choosing the resistor and capacitor values primarily tunes where the center frequency lies and how selective the filter is. The overall gain at the center frequency comes mainly from the amplifier configuration and feedback resistor ratios, not from the pole positions themselves. Noise performance, while influenced by resistor values and the op-amp, is not what these component choices primarily establish.
Question 1
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About this Exam

Prepare with the Operational Amplifier Practice Test practice quiz. This question bank includes 10 questions covering op-amp, voltage, resistor, gain, and input. Use it to review important concepts, identify knowledge gaps, and build confidence for the related exam, course, or assessment.

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Operational Amplifier Practice Test

This practice set contains 10 questions from the matching question bank and focuses on op-amp, voltage, resistor, gain, and input. Work through each question carefully, review the provided solutions, and revisit topics that need more study before your next attempt.

This is an independent study resource intended for practice and review; it is not an official examination or an endorsement by any organization named in the title.

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