Question 1
What is the chemical symbol for the element with the configuration [Xe] 6s² 4f¹¹?
Correct Answer:
Holmium (Ho)
Explanation:
The electron configuration [Xe] 6s² 4f¹¹ corresponds to the element that has a total of 58 electrons in its outer shell, specifically in the 4f and 6s subshells. The notation indicates that the element has the same electron configuration as xenon up to the noble gas core, followed by two electrons in the 6s subshell and eleven electrons in the 4f subshell. This configuration points to an element in the lanthanide series, which includes the f-block elements where the 4f subshell is being filled. When analyzing the number of 4f electrons, we find that all relevant elements leading up to element 71 (lutetium) are indeed in the f-block. Since the configuration specifies 4f¹¹, this directly identifies the element as having the atomic number of 67. Holmium (Ho) is the element with atomic number 67, making it the correct corresponding symbol for this configuration. The presence of the filled 4f subshell contributes significantly to the chemical properties of the element, which include its magnetic and optical characteristics. Hence, the chemical symbol for the element with the configuration [Xe] 6s² 4f
Question 2
What element matches the electron configuration [Xe] 6s^2 4f^14 5d^10 6p^5?
Correct Answer:
Astatine (At)
Explanation:
The electron configuration given is [Xe] 6s² 4f¹⁴ 5d¹⁷ 6p⁷, which indicates that the element has filled subshells (4f and 5d) along with additional electrons in the 6s and 6p orbitals. To analyze this configuration, we can break it down: - The [Xe] represents the electron configuration of xenon, which accounts for the first 54 electrons. - The 6s² indicates that the element has 2 electrons in the 6s subshell. - The 4f¹⁴ indicates that there are 14 electrons fully occupying the 4f subshell. - The 5d¹⁷ signifies that there are 10 electrons in the 5d subshell. - Finally, the 6p⁷ shows that there are 5 electrons in the 6p subshell. To find the total number of electrons, we can add these together: 54 (from xenon) + 2 (from 6s) + 14 (from 4f) + 10 (from 5d) + 5 (from 6p) equals 85
Question 3
Which element corresponds to the electron configuration [Rn] 7s^2 5f^14 6d^6?
Correct Answer:
Hassium (Hs)
Explanation:
The given electron configuration, [Rn] 7s² 5f¹⁴ 6d⁷, indicates that the element in question is in period 7 of the periodic table and contains electrons in the 7s, 5f, and 6d sublevels. To break down the configuration: - The [Rn] denotes the core electrons up to radon, which accounts for 86 electrons. - The 7s² indicates there are 2 electrons in the 7s orbital. - The 5f¹⁴ suggests that the 5f sublevel is fully occupied with its maximum of 14 electrons. - The 6d⁷ points to 6 electrons in the 6d sublevel. When we total these, the electron count is: 86 (from Rn) + 2 (from 7s) + 14 (from 5f) + 6 (from 6d) = 108 electrons. The element with atomic number 108 is Hassium (Hs), which matches the provided electron configuration. This is confirmed by the fact that Hassium is a member of the transactinide series, situated in Group 8 and Period 7
Question 4
Which element has the electron configuration 1s^2?
Correct Answer:
Beryllium
Explanation:
The correct electron configuration for an element denotes how many electrons are present in its atomic structure and how they are distributed among various atomic orbitals. In the case of the configuration 1s^2, it specifies that there are two electrons occupying the 1s orbital. The element that corresponds to this specific electron configuration is helium. Helium has a total of two electrons, which fill the 1s orbital. Understanding that the 1s orbital can hold a maximum of two electrons provides a clearer insight into helium's stability as a noble gas, characterized by a complete outer shell. The other elements listed, such as oxygen, lithium, and beryllium, have different electron configurations. Oxygen has six electrons and would have a configuration of 1s^2 2s^2 2p^4. Lithium, with three electrons, would configure as 1s^2 2s^1, while beryllium, with four electrons, has a configuration of 1s^2 2s^2. Hence, only helium is accurately represented by the configuration 1s^2.
Question 5
[Rn] 7s² 5f⁹ corresponds to which actinide element?
Correct Answer:
Berkelium (Bk)
Explanation:
The electron configuration [Rn] 7s² 5f⁷ corresponds to the element that has a total of 9 electrons in the 5f subshell, which places it within the actinide series of elements. To identify the element based on its electron configuration, it’s helpful to recognize that the actinides are located in the f-block of the periodic table, specifically in the period corresponding to the 5f subshell. The sequence follows the filling of orbitals based on the Aufbau principle, where 5f is filled after the 6d orbitals. Each element in the actinide series has a distinct number of electrons, and the one with the configuration of 5f⁷ is specifically Fermium (Fm). Fermium is known to have an atomic number of 100, which fits the configuration of having 9 electrons in the 5f subshell after Radon (Rn) core. This means that the provided answer does not correctly correspond with the configuration mentioned. To give context, Berkelium (Bk), which is the choice given, corresponds to [Rn] 7s² 5f⁷, indicating that it does not reflect the correct number of electrons in the
Question 1
Exam overview

About this Exam

The Electron Configuration Practice Test is a crucial assessment tool for students navigating the foundational concepts of atomic structure and quantum mechanics. This practice test evaluates your comprehensive understanding of how electrons distribute themselves within atomic orbitals, which is the key to unlocking the predictable chemical properties of all elements. Designed for advanced high school chemistry students (including AP and IB Chemistry programs), first-year university general chemistry students, and individuals preparing for science-focused qualifying exams, this assessment serves as a critical benchmark for mastering one of chemistry's most essential topics. It helps identify knowledge gaps and builds the confidence necessary to succeed in higher-level chemical analysis.

More details

Additional Information

What the Course Entails and Exam Details

This examination does not accompany a single formal course, but rather assesses the syllabus covered in a foundational chemistry unit or a dedicated review module. A structured study plan preparing for this test should focus heavily on quantum theory principles. Core topics you must master include the distinction between energy shells (levels), sublevels (s, p, d, f), and specific orbitals, along with the correct application of defining principles. You will need a deep understanding of the Aufbau Principle (filling lower energy levels first), the Pauli Exclusion Principle (no two electrons in an atom can have the same set of four quantum numbers), and Hund’s Rule (maximizing unpaired electrons in degenerate orbitals). The exam evaluates your ability to write both standard and noble-gas notation configurations for neutral atoms and, significantly, for ions, while navigating common exceptions within the transition metals.


What to Expect in the Final Exam

You should expect this practice exam to be a rigorous, comprehensive assessment typically delivered in an online or standardized written format. A common configuration includes approximately 40 to 60 multiple-choice questions designed to test theoretical knowledge and computational accuracy. You may also encounter short-answer questions requiring you to write full configurations or draw orbital diagrams, demonstrating a procedural understanding of electron filling order. A typical passing score for these targeted subject assessments aims for mastery, often set between 70% and 80%. Time limits are realistic, often ranging from 45 to 90 minutes, simulating the time constraints found in major academic exams. Strict rules apply regarding academic integrity; standard calculators are sometimes permitted but are usually unnecessary as the logic itself is the focus of the evaluation.


How to Study and Exam Centers

Preparation for the Electron Configuration Practice Test requires both conceptual review and persistent practical application. First, solidify your understanding of the quantum numbers (n, l, ml, ms) and their role in defining orbital properties. Use visual aids like the Bohr model to understand main energy levels before transitioning to complex orbital diagrams. Create or find mnemonic devices for the diagonal filling rule, but prioritize understanding the why behind it. Repeatedly practicing writing configurations from a blank periodic table is the single most effective strategy; this includes mastering standard configurations, noble gas abbreviations, and recognizing ions. Focus extensive practice time on the challenging transition metal exceptions, such as Chromium (Cr) and Copper (Cu). Since this is a specialized subject test, it is typically taken via online educational platforms (like Khan Academy, specialized chemistry websites, or learning management systems like Canvas used by your school). It may also be offered as a preliminary assessment within specific academic institutions or tutoring organizations.


Job Opportunities from the Course

A strong understanding of electron configuration is a foundational skill that unlocks countless pathways in higher education and subsequent professional scientific fields.

  • Chemist

  • Chemical Engineer

  • Pharmacist

  • Biochemist

  • Materials Scientist

  • Toxicologist

  • Nuclear Medicine Technologist

  • Forensic Scientist

  • Quality Control Analyst

  • Research Scientist

Quiz information

Frequently Asked Questions

The complete question count is available after full access is unlocked.
No fixed duration is currently configured for this quiz.
Question explanations are included where they are available in the quiz content, helping you review the reasoning after answering.
Yes. You can retake the practice test again as you continue studying during your available access period.
After your access is confirmed, you can continue into the complete practice exam from this quiz flow.
Unless explicitly stated otherwise, this page provides independent practice material for study and exam preparation and is not the official examination itself.
Keep studying

Related Questions