Registered Surveyor Practice Questions - China Registered Surveyor and Mapping Engineer Qualification Examination (全国注册测绘师职业资格考试) Exam - Registered Surveyor Practice Questions - China Registered Surveyor and Mapping Engineer Qualification Examination (全国注册测绘师职业资格考试) Exam

Question 1

Under the China Geodetic Coordinate System 2000 (CGCS2000), which of the following defines the defining geometric parameters of the reference ellipsoid?

Semi-major axis a = 6378137.0 m and flattening f = 1 / 298.257222101 Semi-major axis a = 6378140.0 m and flattening f = 1 / 298.257 Semi-major axis a = 6378245.0 m and flattening f = 1 / 298.3 Semi-major axis a = 6378137.0 m and flattening f = 1 / 298.257223563

Correct Answer:

Semi-major axis a = 6378137.0 m and flattening f = 1 / 298.257222101

Question 2

What is the official origin elevation and baseline tide gauge location for the 1985 National Elevation Datum (1985国家高程基准) in China?

72.260 m above mean sea level determined at the Qingdao Daguan Tide Gauge (1952–1979 observations) 72.289 m above mean sea level determined at the Qingdao Daguan Tide Gauge (1950–1956 observations) 70.000 m above mean sea level determined at the Shanghai Wusong Tide Gauge 75.500 m above mean sea level determined at the Tianjin Dagukou Tide Gauge

Correct Answer:

72.260 m above mean sea level determined at the Qingdao Daguan Tide Gauge (1952–1979 observations)

Question 3

A GNSS survey determines the geodetic height (h) of a control point as 125.450 m relative to the CGCS2000 ellipsoid. If the local height anomaly (ζ) derived from the national quasi-geoid model is -0.320 m, what is the Normal Height (H_normal) of the point under China's national vertical system?

125.770 m 125.130 m 125.450 m -125.130 m

Correct Answer:

125.770 m

Question 4

In high-precision static GNSS baseline processing, why is the double-differenced carrier phase (双差载波相位) observable universally applied?

It completely eliminates receiver clock errors and satellite clock errors simultaneously. It completely eliminates ionospheric delay and tropospheric refraction without requiring empirical models. It directly fixes the carrier phase cycle ambiguities to integers without baseline adjustment. It eliminates multipath effects and receiver antenna phase center variations.

Correct Answer:

It completely eliminates receiver clock errors and satellite clock errors simultaneously.

Question 5

During a static GNSS survey session with m receivers observing simultaneously, what is the total number of simultaneously observed baselines and the number of mathematically independent baselines (独立基线)?

Total baselines = m(m - 1) / 2; Independent baselines = m - 1 Total baselines = m(m - 1); Independent baselines = m Total baselines = m - 1; Independent baselines = m(m - 1) / 2 Total baselines = m^2; Independent baselines = 2m - 1

Correct Answer:

Total baselines = m(m - 1) / 2; Independent baselines = m - 1

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About this Exam

Prepare with the Registered Surveyor Practice Questions - China Registered Surveyor and Mapping Engineer Qualification Examination (全国注册测绘师职业资格考试) Exam practice quiz. This question bank includes 100 questions covering geodetic, point, china, coordinate, and height. Use it to review important concepts, identify knowledge gaps, and build confidence for the related exam, course, or assessment.

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Registered Surveyor Practice Questions - China Registered Surveyor and Mapping Engineer Qualification Examination (全国注册测绘师职业资格考试) Exam

This practice set contains 100 questions from the matching question bank and focuses on geodetic, point, china, coordinate, and height. Work through each question carefully, review the provided solutions, and revisit topics that need more study before your next attempt.

This is an independent study resource intended for practice and review; it is not an official examination or an endorsement by any organization named in the title.

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Registered Surveyor Practice Questions - China Registered Surveyor and Mapping Engineer Qualification Examination (全国注册测绘师职业资格考试) Exam

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