ENADE Física Practice Questions - ENADE Física - Exame Nacional de Desempenho dos Estudantes Exam - ENADE Física Practice Questions - ENADE Física - Exame Nacional de Desempenho dos Estudantes Exam

Question 1

A projectile of mass $m$ is launched vertically upward from the ground with initial velocity $v_0$ in a viscous medium experiencing linear drag $\vec{F}_{drag} = -b\vec{v}$, where $b > 0$. With gravitational acceleration $g$ directed downward, what is the terminal velocity magnitude $v_{ter}$ during free fall and the velocity function $v(t)$ during upward ascent?

$$v_{ter} = \frac{b}{mg}$ and $v(t) = v_0 e^{-\frac{b}{m}t} - gt$ $$v_{ter} = \sqrt{\frac{mg}{b}}$ and $v(t) = \left(v_0 - \frac{mg}{b}\right)e^{-\frac{b}{m}t} + \frac{mg}{b}$ $$v_{ter} = \frac{mg}{b}$ and $v(t) = \left(v_0 + \frac{mg}{b}\right)e^{-\frac{b}{m}t} - \frac{mg}{b}$ $$v_{ter} = \frac{mg}{b}$ and $v(t) = v_0 \cos\left(\frac{b}{m}t\right) - \frac{mg}{b}\sin\left(\frac{b}{m}t\right)$

Correct Answer:

$$v_{ter} = \frac{mg}{b}$ and $v(t) = \left(v_0 + \frac{mg}{b}\right)e^{-\frac{b}{m}t} - \frac{mg}{b}$

Question 2

In a conservative central force field with potential $V(\vec{r}) = V(r)$, the orbital angular momentum $\vec{L} = \vec{r} \times \vec{p}$ is a conserved constant of motion. Consequently, the position vector sweeps out area at a constant rate (Kepler's Second Law). What is the magnitude of this areal velocity $\frac{dA}{dt}$ in terms of $L$ and particle mass $m$?

$$\frac{dA}{dt} = \frac{L}{m}$ $$\frac{dA}{dt} = \frac{L}{2m}$ $$\frac{dA}{dt} = \frac{2L}{m}$ $$\frac{dA}{dt} = \frac{L^2}{2m}$

Correct Answer:

$$\frac{dA}{dt} = \frac{L}{2m}$

Question 3

A two-body isolated gravitational system consists of masses $m_1$ and $m_2$ separated by distance $r$. Transforming the dynamics to the center-of-mass frame reduces the system to a single fictitious particle of reduced mass $\mu$ moving in central potential $V(r) = -\frac{G m_1 m_2}{r}$. What are the expressions for $\mu$ and total kinetic energy $T_{CM}$ in polar coordinates $(r, \theta)$?

$$\mu = \frac{m_1 m_2}{m_1 + m_2}$ and $T_{CM} = \frac{1}{2}\mu \dot{r}^2 + \frac{L^2}{2\mu r^2}$ $$\mu = \sqrt{m_1 m_2}$ and $T_{CM} = \frac{1}{2}\mu (\dot{r}^2 + r^2 \dot{\theta}^2)$ $$\mu = \frac{m_1 + m_2}{2}$ and $T_{CM} = \frac{1}{2}\mu \dot{r}^2 + \frac{L^2}{2(m_1+m_2) r^2}$ $$\mu = \frac{m_1 m_2}{m_1 + m_2}$ and $T_{CM} = \frac{1}{2}(m_1+m_2)\dot{r}^2 + \frac{L^2}{2\mu r^2}$

Correct Answer:

$$\mu = \frac{m_1 m_2}{m_1 + m_2}$ and $T_{CM} = \frac{1}{2}\mu \dot{r}^2 + \frac{L^2}{2\mu r^2}$

Question 4

A damped harmonic oscillator of mass $m$, natural undamped frequency $\omega_0$, and damping parameter $\gamma = b/(2m)$ is driven by external periodic force $F(t) = F_0 \cos(\omega t)$. What is the driving frequency $\omega_r$ that maximizes the steady-state position oscillation amplitude $A(\omega)$, assuming underdamping $\gamma < \omega_0 / \sqrt{2}$?

$$\omega_r = \omega_0$ $$\omega_r = \sqrt{\omega_0^2 - \gamma^2}$ $$\omega_r = \sqrt{\omega_0^2 + 2\gamma^2}$ $$\omega_r = \sqrt{\omega_0^2 - 2\gamma^2}$

Correct Answer:

$$\omega_r = \sqrt{\omega_0^2 - 2\gamma^2}$

Question 5

A uniform thin rod of mass $M$ and length $L$ has moment of inertia $I_{CM} = \frac{1}{12}M L^2$ about its center of mass. By the Parallel Axis Theorem (Steiner's Theorem), what is the rod's moment of inertia about a perpendicular axis located at a distance $d = L/4$ from one of its ends?

$$\frac{1}{16} M L^2$ $$\frac{7}{48} M L^2$ $$\frac{1}{3} M L^2$ $$\frac{19}{48} M L^2$

Correct Answer:

$$\frac{7}{48} M L^2$

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Prepare with the ENADE Física Practice Questions - ENADE Física - Exame Nacional de Desempenho dos Estudantes Exam practice quiz. This question bank includes 100 questions covering frac, omega, text, mass, and partial. Use it to review important concepts, identify knowledge gaps, and build confidence for the related exam, course, or assessment.

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ENADE Física Practice Questions - ENADE Física - Exame Nacional de Desempenho dos Estudantes Exam

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