A-5 Excavating And Grading Practice Exam

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A ball is thrown vertically upwards with an initial speed of 18 m s^-1. Taking g as 9.8 m s^-2, what is its maximum height above the release point?
Correct Answer:
16.5 m
Explanation:
At maximum height v = 0. Using v^2 = u^2 + 2as gives 0 = 18^2 - 2(9.8)s, so s = 324/19.6 = 16.5 m.

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