Red Seal Hairstylist Practice Exam

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What is the pH of a 0.050 mol dm⁻³ aqueous solution of barium hydroxide, Ba(OH)₂, at 298 K? (Kw = 1.0 x 10⁻¹⁴)
Correct Answer:
13.00
Explanation:
Ba(OH)₂ fully dissociates to release 2 OH⁻ ions per molecule. [OH⁻] = 0.050 * 2 = 0.100 mol dm⁻³. pOH = -log(0.1) = 1. pH = 14 - 1 = 13.00.

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