Bangladesh Healthcare Practice Test & Exam Prep

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What is the moment of inertia (I) of a uniform solid circular disc of mass M and radius R about an axis passing through its center and perpendicular to its plane?

I = (1/2) * M * R² I = M * R² I = (2/5) * M * R² I = (1/4) * M * R²

Correct Answer:

I = (1/2) * M * R²

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