BHS-Matura Practice Questions - Austria BHS-Reife- Und Diplomprüfung (Vocational Matura) Exam

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The temperature T(t) (in °C) of an industrial component cooling in ambient air (20°C) is modeled by Newton's Law of Cooling: T(t) = 20 + 80 · e^(-0.05t), where t is time in minutes. What is the component's temperature at t = 0 and after t = 20 minutes? (Use e^(-1) ≈ 0.3679).

T(0) = 100°C; T(20) ≈ 49.43°C T(0) = 80°C; T(20) ≈ 49.43°C T(0) = 100°C; T(20) ≈ 29.43°C T(0) = 120°C; T(20) ≈ 59.43°C

Correct Answer:

T(0) = 100°C; T(20) ≈ 49.43°C

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