SC Heating Practice Questions - South Carolina Heating Contractor Examination Exam

The conduction heat loss through a wall, roof, or glass is calculated with which relationship?

Q = 1.08 × CFM × ΔT only, with no area term Q = U × A × ΔT, where U is the assembly U-factor, A is area, and ΔT is the indoor-to-outdoor temperature difference Q = 500 × GPM × ΔT only Q = heating surface × 240, regardless of the assembly

Correct Answer:

Q = U × A × ΔT, where U is the assembly U-factor, A is area, and ΔT is the indoor-to-outdoor temperature difference

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