Biomedical Engineering (BME) 3 Practice Test

Acoustic impedance Z = ρ c. If ρ = 1000 kg/m^3 and c = 1540 m/s, Z ≈ ?

1.00×10^6 Pa·s/m 1.54×10^6 Pa·s/m 1.54×10^3 Pa·s/m 1.00×10^3 Pa·s/m

Correct Answer:

1.54×10^6 Pa·s/m

Explanation:

Acoustic impedance for a plane wave in a medium is the product of its density and the speed of sound: Z = ρ c. With ρ = 1000 kg/m^3 and c = 1540 m/s, multiply to get Z = 1000 × 1540 = 1.54 × 10^6. The units come out as Pa·s/m, since kg/m^3 times m/s equals kg/(m^2 s), which is the standard unit for acoustic impedance. So the correct value is 1.54 × 10^6 Pa·s/m. Other numbers would result from using a different speed or density.

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