TExES Math 4-8 (115) Practice Questions - TExES Mathematics 4-8 (115) Exam

A student claims that 0.999... (repeating) is less than 1. Which argument correctly shows the two values are equal?

Let x = 0.999...; then 10x = 9.999..., so 10x - x = 9, giving 9x = 9 and x = 1 0.999... rounds up to 1, so they are equal 0.999... has infinitely many digits, so it cannot equal a whole number Since 0.999... never reaches 1, the values are only approximately equal

Correct Answer:

Let x = 0.999...; then 10x = 9.999..., so 10x - x = 9, giving 9x = 9 and x = 1

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