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AQA GCSE Triple Science – Physics Practice Test

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A 2 kg block on a frictionless surface is raised to height h = 3 m. What is the kinetic energy at the bottom? Use g = 9.8 m/s^2.
Correct Answer:
58.8 J
Explanation:
Energy is conserved on a frictionless path, so the block’s loss of gravitational potential energy as it descends becomes kinetic energy. At the bottom, all the initial potential energy has turned into kinetic energy, so KE = m g h. Using m = 2 kg, g = 9.8 m/s^2, and h = 3 m gives KE = 2 × 9.8 × 3 = 58.8 J. That’s why the kinetic energy at the bottom is 58.8 J. If you wanted the speed, you’d relate KE to velocity with KE = 1/2 m v^2, giving v = sqrt(2 g h) ≈ 7.7 m/s. The other numbers don’t match m g h for these values, so they don’t fit the bottom-energy result.

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