UGA Math Placement Practice Exam

When a coin is flipped, it has two possible outcomes for each flip: it can either land on heads or tails. To determine the total number of possible outcomes when flipping a coin multiple times, you can use the formula \(2^n\), where \(n\) is the number of flips. In this case, since the coin is flipped 10 times, you would calculate \(2^{10}\). Here’s how that breaks down: - The first flip has 2 outcomes. - The second flip, independent of the first, also has 2 outcomes. - This pattern continues for all 10 flips. Therefore, the total number of outcomes is: \[ 2^{10} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 1024 \] Thus, the total number of possible outcomes when a coin is flipped 10 times is 1024. This is why the choice of 1024 is the correct answer in this scenario.