RBSE SS Chemistry Practice Questions - Rajasthan RBSE Senior Secondary (Class 12) Chemistry - Code 041 Exam

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A 0.10 m aqueous solution of a non-volatile non-electrolyte freezes at −0.186 °C. If K_f for water is 1.86 K kg mol⁻¹, the depression of freezing point confirms that

ΔT_f = K_f · m = 0.186 K ΔT_f = K_f / m = 18.6 K ΔT_f = K_f · m² = 0.0186 K ΔT_f is independent of molality for non-electrolytes

Correct Answer:

ΔT_f = K_f · m = 0.186 K

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