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OnRamps Physics Practice Test
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What is the expression for the sound intensity I in terms of the source power P and the area A over which the power spreads?
I = P*A
I = A/P
I = P/A
I = P^2/A^2
Reveal Answer
Correct Answer:
I = P/A
Explanation:
Sound intensity is the power per unit area—the rate at which energy passes through a given area. If a source emits power P and that power spreads over an area A, the intensity is I = P/A. This makes intuitive sense: more area means the same amount of power is spread thinner, so the intensity goes down in proportion to 1/A. In free space, a point source radiates over a spherical area A = 4πr^2, giving I = P/(4πr^2). The units are watts per square meter. Expressions that multiply by area or square the power don’t match the idea of energy crossing area, which is why they aren’t correct.
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