IB Mathematics Analysis And Approaches HL Practice Questions - International Baccalaureate Mathematics Analysis And Approaches Higher Level Exam

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Prove by induction that 1+2+3+...+n = n(n+1)/2. The inductive step assumes P(k): 1+2+...+k = k(k+1)/2. What is the next step to show P(k+1)?

Add (k+1) to both sides Multiply both sides by (k+1) Differentiate both sides with respect to k Substitute k = 1 again

Correct Answer:

Add (k+1) to both sides

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